{"id":5373,"date":"2020-08-05T08:17:15","date_gmt":"2020-08-05T08:17:15","guid":{"rendered":"https:\/\/panekspanel.com\/eng\/?p=5373"},"modified":"2020-08-05T08:17:15","modified_gmt":"2020-08-05T08:17:15","slug":"soguk-depo-nemlendirme-hesaplamasi","status":"publish","type":"post","link":"https:\/\/panekspanel.com\/eng\/2020\/08\/05\/soguk-depo-nemlendirme-hesaplamasi\/","title":{"rendered":"So\u011fuk Depo Nemlendirme Hesaplamas\u0131"},"content":{"rendered":"

SO\u011eUK DEPO NEMLEND\u0130RME HESAPLAMASI<\/strong><\/p>\n

\u00d6zellikle end\u00fcstriyel tip so\u011fuk depolarda saklanan \u00fcr\u00fcnlerin sabit bir nem oran\u0131nda tutulmas\u0131 b\u00fcy\u00fck \u00f6nem ta\u015f\u0131maktad\u0131r. Sebze ve meyve depolar\u0131nda %80 ila %95 aras\u0131nda de\u011fi\u015fen nem ihtiyac\u0131n\u0131 do\u011fal yollardan sa\u011flamak olanakl\u0131 de\u011fildir. So\u011fuk depolarda yer alan evoparat\u00f6rler tam da bu nem ihtiyac\u0131n\u0131n tersi y\u00f6nde birer nem al\u0131c\u0131 gibi \u00e7al\u0131\u015fmaktad\u0131rlar.<\/p>\n

Cebri bir nemlendirme yap\u0131lmad\u0131ysa ortalama %70 nem ile evoperat\u00f6re giren so\u011fuk hava burada evaporat\u00f6r i\u00e7inden ge\u00e7irilirken teorik olarak %100 oran\u0131nda ama daha d\u00fc\u015f\u00fck bir s\u0131cakl\u0131kta ( genellikle Eurovent \u015fartlar\u0131nda bu oran delta T= 8 \u2018dir.Ancak nem duyarl\u0131l\u0131\u011f\u0131 y\u00fcksek \u00fcr\u00fcnlerde evaporat\u00f6r y\u00fczeyleri daha b\u00fcy\u00fck se\u00e7ilerek bu oran genellikle delta5 \u2018e kadar d\u00fc\u015f\u00fcr\u00fcl\u00fcr. ) ve daha d\u00fc\u015f\u00fck bir \u00f6zg\u00fcl nemde (g\/ kg kuru hava) depo i\u00e7ine g\u00f6nderilir. Dolay\u0131s\u0131yla asl\u0131nda b\u00fct\u00fcn evoparat\u00f6rler birer nem al\u0131c\u0131d\u0131rlar ve bu y\u00fczden so\u011fuk depolarda ba\u011f\u0131l nem ancak \u00f6nceden hesaplanmal\u0131 ve bir nemlendirme cihaz\u0131yla kar\u015f\u0131lanabilecek \u015fekilde dikkate al\u0131nmal\u0131d\u0131r.<\/p>\n

\"\"<\/p>\n

 <\/p>\n

1.So\u011fuk Depolarda \u0130nfiltrasyon Ve S\u0131z\u0131nt\u0131lar Kaynakl\u0131 Nem Kayb\u0131 :<\/strong><\/p>\n

So\u011fuk depolarda kap\u0131 a\u00e7\u0131lma s\u0131kl\u0131\u011f\u0131 ve s\u0131z\u0131nt\u0131 kaynakl\u0131 nem kayb\u0131 i\u00e7in de\u011fi\u015fik ve detayl\u0131 hesaplama teknikleri olmakla birlikte bu konuda olu\u015fturulmu\u015f hesaplama y\u00f6ntemleri vard\u0131r. Ancak biz burada pratik hesaplama tablolar\u0131n\u0131 dikkate alaca\u011f\u0131z. Bunun as\u0131l nedeni hesaplama sonunda da g\u00f6r\u00fclebilece\u011fi gibi infiltrasyon ve s\u0131zma kaynakl\u0131 nem kayb\u0131n\u0131n evaporat\u00f6r kaynakl\u0131 nem kayb\u0131 yan\u0131nda \u00e7ok k\u00fc\u00e7\u00fck kalmas\u0131d\u0131r.<\/p>\n

Bu konuda \u00f6rnek olarak se\u00e7ilen depo 900 m3 ebatlar\u0131nda (15 x 10 x 6 m) bir so\u011fuk depodur. Depomuz tipik bir elma deposu olup %95 nem ihtiyac\u0131 olan bir depodur ve<\/p>\n

so\u011fuk depo i\u00e7 s\u0131cakl\u0131\u011f\u0131 +2 C\u2018dir. (1*. syf.11.2 ) Evaporasyon s\u0131cakl\u0131\u011f\u0131 – 3 C olarak al\u0131nm\u0131\u015ft\u0131r. Depo d\u0131\u015f\u0131ndaki s\u0131cakl\u0131k +30 C ve ba\u011f\u0131l nem %50 olarak al\u0131nm\u0131\u015ft\u0131r.<\/p>\n

Bu so\u011fuk depo i\u00e7in pratik hesaplarla ortaya \u00e7\u0131kan hava de\u011fi\u015fimi enterpolasyon y\u00f6ntemiyle 2,66 olarak bulunur. (2*. syf.354 ) Burada so\u011fuk depo kap\u0131s\u0131 a\u00e7\u0131lma s\u0131kl\u0131\u011f\u0131 ortalama olarak al\u0131nm\u0131\u015ft\u0131r. Yo\u011fun kullan\u0131mda hava de\u011fi\u015fim oran\u0131 %50 ila %100 oran\u0131nda artt\u0131r\u0131labilir.<\/p>\n

So\u011fuk Depoya Giren D\u0131\u015f Hava Miktar\u0131 = Oda Hacmi x Hava De\u011fi\u015fimi<\/p>\n

So\u011fuk Depoya Giren D\u0131\u015f Hava Miktar\u0131 = 900 x 2,66<\/p>\n

So\u011fuk Depoya Giren D\u0131\u015f Hava Miktar\u0131 =2.394 m3\/g\u00fcn<\/p>\n

So\u011fuk depoya giren hava , i\u00e7erde so\u011fuk depo havas\u0131yla kar\u015f\u0131la\u015farak so\u011fuk depo s\u0131cakl\u0131\u011f\u0131 ve nemine kadar de\u011fi\u015fim g\u00f6sterecektir. Bu durumda ortaya \u00e7\u0131kan nem kayb\u0131 i\u00e7in \u00f6ncelikle \u00f6zg\u00fcl nemdeki de\u011fi\u015fimi bulmal\u0131y\u0131z. Bu ise ;<\/p>\n

So\u011fuk depoya Giren Hava \u00f6zg\u00fcl Nemi= 13,36 gr \/Kg kuru hava<\/p>\n

Evaporat\u00f6r \u00c7\u0131k\u0131\u015f Havas\u0131 \u00f6zg\u00fcl Nemi = 4,16 gr \/Kg kuru hava<\/p>\n

Aras\u0131ndaki fark ile bulunabilir;<\/strong><\/p>\n

\u0130nfiltrasyon Nedeni \u0130le Olu\u015fan Su Kayb\u0131 = (D\u0131\u015f Hava Debisi\/\u00d6zg\u00fcl hacim ) x (\u00f6zg\u00fcl nem fark\u0131 )<\/p>\n

\u0130nfiltrasyon Nedeni \u0130le Olu\u015fan Su Kayb\u0131 =( 2.394 \/ 0,878) x (13,36\u2013 4,16 ) =25.085 gr\/g\u00fcn =25, 08 kg\/g\u00fcn<\/p>\n

Ortalama 10 saatlik kap\u0131 giri\u015f \u00e7\u0131k\u0131\u015f kaynakl\u0131 depo kullan\u0131m\u0131 dikkate al\u0131nd\u0131\u011f\u0131nda bunu 10\u2019a b\u00f6lersek;<\/p>\n

\u0130nfiltrasyon Nedeni \u0130le Olu\u015fan Su Kayb\u0131 = 2,51 kg\/ saat\u00a0\u00a0 olarak buluruz.<\/p>\n

 <\/p>\n

2.So\u011fuk Depolarda Evaporasyon Nedeniyle Olu\u015fan Nem Kayb\u0131 :<\/strong><\/p>\n

Evaporat\u00f6rdeki s\u0131cakl\u0131k d\u00fc\u015f\u00fcm\u00fc s\u0131ras\u0131nda e\u015fanj\u00f6r y\u00fczeyinde ortaya \u00e7\u0131kan nem kayb\u0131 as\u0131l dikkate almam\u0131z gereken nem kayb\u0131d\u0131r. Bu ise depoya depo set de\u011feri s\u0131cakl\u0131\u011f\u0131nda giren havan\u0131n ortalama 8 deltaT ile evaporat\u00f6r lamellerini terk ederken s\u0131cakl\u0131k d\u00fc\u015f\u00fcm\u00fc nedeniyle b\u0131rakt\u0131\u011f\u0131 nemdir. Bunun i\u00e7in evaporat\u00f6rde dola\u015fan hava miktar\u0131n\u0131 yani hava debisini bilmemiz gereklidir. Bu \u00f6rnekte ise nem duyarl\u0131l\u0131\u011f\u0131 y\u00fcksek olan bir \u00fcr\u00fcn i\u00e7in b\u00fcy\u00fck y\u00fczey alanl\u0131 bir evaporat\u00f6r se\u00e7ilmi\u015f olup deltaT=5 al\u0131nm\u0131\u015ft\u0131r.<\/p>\n

\u00d6rnek ald\u0131\u011f\u0131m\u0131z so\u011fuk depo i\u00e7in depo b\u00fcy\u00fckl\u00fc\u011f\u00fc dikkate al\u0131narak 2 adet evaporat\u00f6r se\u00e7ildi\u011fi ve bunlar\u0131n her birinin 3 adet 500 mm \u00e7apl\u0131 fanlardan ibaret oldu\u011fu d\u00fc\u015f\u00fcn\u00fclm\u00fc\u015ft\u00fcr. Bunun i\u00e7in toplam evaporat\u00f6r debisi 20.000 m3\/h al\u0131nm\u0131\u015ft\u0131r.(3*.syf.6 FEH.5031 i\u00e7in ) .Toplam 2 evaporat\u00f6r i\u00e7in bu de\u011fer 2 x 20.000 m3\/h = 40.000 m3\/h \u2018dir.<\/p>\n

So\u011fuk depo ilk devreye alma s\u0131ras\u0131nda depo i\u00e7indeki nem oran\u0131 ba\u015flang\u0131\u00e7ta d\u0131\u015f hava ba\u011f\u0131l nem oran\u0131na yak\u0131nd\u0131r. Ancak devreye alma ile birlikte bu oran e\u011fer i\u00e7erde bir nemlendirici varsa istenilen nem set de\u011ferine kadar y\u00fckselir. Bizim yapmam\u0131z gereken ilk \u00e7al\u0131\u015ft\u0131rma s\u0131ras\u0131ndaki nem kayb\u0131n\u0131 de\u011fil , g\u00fcnl\u00fck ola\u011fan kullan\u0131m s\u0131ras\u0131ndaki nem kayb\u0131n\u0131 bulmakt\u0131r.<\/p>\n

Bu oran ise set nem de\u011feri olan %95\u2019 dir. (. (Ancak nem kay\u0131na duyarl\u0131 ve \u00e7ok h\u0131zl\u0131 nemlendirilmesi gereken \u00fcr\u00fcnlerde ise bu oran\u0131 %60 olarak dikkate al\u0131p 12-36 saat i\u00e7inde istenilen nem de\u011ferine ula\u015facak \u015fekilde hesaplama yapmak gerekir.<\/p>\n

Nemlendirici yokken nem kayb\u0131n\u0131 hesaplamak i\u00e7in so\u011fuk depo nem oran\u0131 %70-80 aras\u0131nda al\u0131nabilir.)<\/p>\n

Evaporat\u00f6r i\u00e7inden ge\u00e7en hava ise teorik olarak %100 doyma s\u0131cakl\u0131\u011f\u0131nda d\u00fc\u015f\u00fcn\u00fclse de bu pratikte %95 civar\u0131ndad\u0131r ve bizim hesaplamam\u0131zda %95 olarak al\u0131nm\u0131\u015ft\u0131r.<\/p>\n

So\u011fuk Depo %95 ba\u011f\u0131l nem ve +2 C i\u00e7in \u00d6zg\u00fcl Nem Miktar\u0131 = 4,16 gr \/Kg Kuru hava<\/p>\n

Evaporat\u00f6r \u0130\u00e7indeki Ge\u00e7en Havan\u0131n %95 ba\u011f\u0131l nem ve -3 C i\u00e7in \u00d6zg\u00fcl Nem Miktar\u0131 = 2,80 gr \/Kg Kuru hava<\/p>\n

Evaporasyon Nedeniyle Olu\u015fan Su K\u00fctlesi Kayb\u0131 = (Hava Debisi \/\u00d6zg\u00fcl Hacim ) x \u00d6zg\u00fcl nem Fark\u0131<\/p>\n

Evaporasyon Nedeniyle Olu\u015fan Su K\u00fctlesi Kayb\u0131 = (40.000 \/ 0,79) x(4,16-2,80 )<\/p>\n

Evaporasyon Nedeniyle Olu\u015fan Su K\u00fctlesi Kayb\u0131=68.860 gr \/saat = 68,9 kg\/saat<\/p>\n

G\u00f6r\u00fcld\u00fc\u011f\u00fc gibi evaporasyon nedeniyle olu\u015fan su k\u00fctlesi kayb\u0131 68,9 lt\/saat iken kap\u0131 a\u00e7\u0131lma s\u0131kl\u0131\u011f\u0131 nedeniyle ortaya \u00e7\u0131kan kay\u0131p yaln\u0131zca 2,51 lt\/h \u2018dir.<\/p>\n

Toplam Kay\u0131p = Evaporasyon Nedeniyle Olu\u015fan Su K\u00fctlesi Kayb\u0131 + \u0130nfiltrasyon Nedeni \u0130le Olu\u015fan Su Kayb\u0131<\/p>\n

Toplam Kay\u0131p= 68,9 + 2,51 = 71,41 lt\/saat \u2018dir.<\/p>\n","protected":false},"excerpt":{"rendered":"

SO\u011eUK DEPO NEMLEND\u0130RME HESAPLAMASI \u00d6zellikle end\u00fcstriyel tip so\u011fuk depolarda saklanan \u00fcr\u00fcnlerin sabit bir nem oran\u0131nda tutulmas\u0131 b\u00fcy\u00fck \u00f6nem ta\u015f\u0131maktad\u0131r. Sebze ve meyve depolar\u0131nda %80 ila %95 aras\u0131nda de\u011fi\u015fen nem ihtiyac\u0131n\u0131 do\u011fal yollardan sa\u011flamak olanakl\u0131 de\u011fildir. So\u011fuk depolarda yer alan evoparat\u00f6rler tam da bu nem ihtiyac\u0131n\u0131n tersi y\u00f6nde birer nem al\u0131c\u0131 gibi \u00e7al\u0131\u015fmaktad\u0131rlar. Cebri bir nemlendirme…<\/p>\n","protected":false},"author":1,"featured_media":5375,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[73,74],"post_series":[],"class_list":["post-5373","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-teknik-bilgiler","tag-soguk-oda-nemlendirme","tag-soguk-oda-nemlendirme-hesabi","entry","has-media"],"_links":{"self":[{"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/posts\/5373"}],"collection":[{"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/comments?post=5373"}],"version-history":[{"count":1,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/posts\/5373\/revisions"}],"predecessor-version":[{"id":5376,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/posts\/5373\/revisions\/5376"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/media\/5375"}],"wp:attachment":[{"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/media?parent=5373"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/categories?post=5373"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/tags?post=5373"},{"taxonomy":"post_series","embeddable":true,"href":"https:\/\/panekspanel.com\/eng\/wp-json\/wp\/v2\/post_series?post=5373"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}